Question

If the law of conservation of mass was to hold true, then 20.8 g of BaCl₂, on reaction with 9.8 g of H₂SO₄ will produce 7.3 g of HCl and _______ of BaSO₄.
(A) 11.65 g
(B) 23.3 g
(C) 25.5 g
(D) 30.6 g

Answer 1

First add LHS reaction
20.8+9.8=30.6
Now, 30.6-7.3=23.3
So the answer is 23.3 g

Answer 2

Answer:

23.3 g

option B

Explanation:

If the law of conservation of mass was to hold true, then 20.8 g of BaCl₂, on reaction with 9.8 g of H₂SO₄ will produce 7.3 g of HCl and _______ of BaSO₄.

(A) 11.65 g  

(B) 23.3 g

(C) 25.5 g  

(D) 30.6 g

the law of conservation of mass means mass remains same

Let say X g of BaSO₄ is produced

20.8 g of BaCl₂ + 9.8 g of H₂SO₄ = 7.3 g of HCl +  X g of BaSO₄.

20.8 + 9.8  = 7.3 + X

=> 30.6 = X + 7.3

=> X = 30.6 - 7.3

=> X = 23.3 g

option B is correct