Question

If the LCM and HCF of any two numbers are 27 and 8, find the product of the numbers.

Answer 1

Answer:

I think

Step-by-step explanation:

For two numbers a and b, we know that

(a×b)=HCFof(a,b)×LCMof(a,b)

Here,

a=54,HCF=27,LCM=162

Therefore,

(54×b)=(27×162)

b=

54

27×162

=81

Hence, the other number is 81.

Answer 2

Answer :—

$\longmapsto\tt\bf$ LCM × HCF = Product Of The Number .

$\longmapsto\tt\bf$ 27 × 8 = 216 .

The Product of The Number is 216.