If the LCM and HCF of polynomials p(x) & q(x) are (x - 2) & (x + 3) then p(x) x is
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Given:
p(x)=?
q(x)=4(x+2)(x+3)
L.C.M =12(x
2
−4)=12(x+2)(x−2)
So, H.C.F = (x−1)(x+3)
Using the formula,
p(x)×q(x)= H.C.F × L.C.M
p(x)=
4(x+2)(x+3)
12(x+2)(x−2)(x−1)(x+3)
=3(x−1)(x−2)
Therefore, p(x) is 3(x−1)(x−2).
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