Question

If the lcm and hcf of two number is 1260 and 900 find the product of the number if one is 320

Answer 1

Answer:

Let a is the LCM and b is the HCF of two numbers.

Given, a + b = 1260 ..............1

and a = b + 900 ...............2

Put value of a in equation 1, we get

b + 900 + b = 1260

=> 2b + 900 = 1260

=> 2b = 1260 - 900

=> 2b = 360

=> b = 360/2

=> b = 180

From equation 1, we get

a + 180 = 1260

=> a = 1260 - 180

=> a = 1080

So, LCM = a = 1080

and HCF = b = 180

Now, product of two numbers = LCM * HCF

=> product of two numbers = 1080 * 180

Step-by-step explanation:

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Answer 2

Let ' x ' be the LCM and ' y ' be the HCF of two numbers.

Given ,,,

x + y = 1260 -----(1)

x = y + 900 -----(2)

Put (2) in (1) ,,,,

x + y = 1260

y + 900 + y = 1260

2y = 1260 - 900

2y = 360

y = 180

Put y = 180 in (2) ,,,

x = y + 900

x = 180 + 900

x = 1080

LCM = x = 1080

HCF = y = 180

Now,,, WKT,,,, Product of two no's = LCM × HCF

= 1080 × 180

Product of two no's is 194400 .

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