Math, asked by swathigangireddy27, 4 months ago

If the LCM and HCF of two numbers are 180 and 12 and one of those numbers 60 find the other​

Answers

Answered by ryq1319
0

Answer:

product of 2 no's =lcm*hcf

x*60=180*12

x=36

Step-by-step explanation:

Answered by madeducators3
0

Given:

LCM=180

HCF=12

One number=60

To find:

remaining number

Solution:

we have to know that,

LCM×HCF=One number ×remaining number

put the given value, we get

180×12=60×remaining number

remaining number=\frac{180}{60}×12

solve

remaining number=3×12

                              =36

Hence, the remaining number=36

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