If the LCM and HCF of two numbers are 180 and 12 and one of those numbers 60 find the other
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Answer:
product of 2 no's =lcm*hcf
x*60=180*12
x=36
Step-by-step explanation:
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Given:
LCM=180
HCF=12
One number=60
To find:
remaining number
Solution:
we have to know that,
LCM×HCF=One number ×remaining number
put the given value, we get
180×12=60×remaining number
remaining number=×12
solve
remaining number=3×12
=36
Hence, the remaining number=36
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