Question

if the lcm of (p,q) = 6 and hcf of (p,q) = 2 then find p^2q^2 (please fast)

Answer 1

Answer:

144

Step-by-step explanation:

product of the two numbers Will be equal to product of LCM and HCF

p × q = 2 × 6

p × q = pq = 12

${p}^{2} {q}^{2} = {(pq)}^{2} \\ {12}^{2} = 144$

Answer 2

Answer:

The value of p²q² = 144

Step-by-step explanation:

Given

LCM (p,q) = 6

HCF(p,q) = 2

To find,

The value of p²q²

Recall the formula

Product of two numbers = LCM×HCF

Solution:

The given numbers p and q

We have LCM (p,q) = 6 and HCF(p,q) = 2

HCF(p,q)×LCM(p,q) = 6×2 = 12

Product of the two numbers = pq

Since the Product of two numbers = LCM×HCF, we have

pq = 12

Squaring on both sides = (pq)² = 144

p²q² = 144

∴ The value of p²q² = 144

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