if the LCM of two prime number a and b is 253,then the value of 8b-3a
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Answered by
44
Answer:
LCM of two number is always product of both the number
SO, In this case 253 =a*b
Factors of 253 are 11and23
8b=11*8 =88
3a=23*3 =69
8b-3a=80-69=19
Answered by
4
Given:
LCM of two prime numbers, a and b is 253
To find:
the value of 8b-3a
Solution:
As both, the numbers are prime numbers (which means that they are divisible only by 1 or themselves) it is not possible for them to have any factors and the product of both these numbers a and b is equal to 253
a×b = 253
LCM stands for the least common multiple,
LCM ( a,b)
= 253
= 23 × 11 × 1
so we obtain
a = 23
b = 11
Now substituting the values in 8b-3a
=8b-3a
It can either be
= 184 - 33
= 151
OR
a = 11
b = 23
= 88-69
=19
Therefore the value of 8b-3a is either 151 or 10.
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