If the least number of six digits which when divided by 4, 6, 10 and 15 leaves the same remainder of 2 in each case is N. The the sum of the digits of N is?
A. 3
B. 4
C. 5
D. 6
please help.....
Answers
Answered by
11
Answer:
Option C
Step-by-step explanation:
LCM of 4, 6, 10, 15 = 60
Least number of 6 digits = 100000
The least number of 6 digits which is exactly divisible by 60 = 100000 + (60 – 40) = 100020
∴ Required Number = 100020 + 2 = 100022
Hence, the sum of digits = 1 + 0 + 0 + 0 + 2 + 2 = 5
Hence option [C] is correct answer.
#answerwithquality #BAL
Answered by
0
Answer:
C. 5 is the correct answer
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