Question

if the leg of a right angled triangle is 5 and base is 12 then what is the hypotenuse​

Answer 1

$hypotenuse = \sqrt{a {}^{2} + b {}^{2} } \\ (where \: a \: and \: b \: are \: the \: sides \: of \: right \: angled\:triangle) \\ \sqrt{5 { }^{2} + 12 {}^{2} } \\ = \sqrt{169} \\ = 13$

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