Question

If the lenght of a rectangle exceeds its breadth by 10 meters .Its permeter is 40m (let the breadth of rectangle be a meter)

Answer 1

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⭕Let the breadth be x m.

So length is( x + 10)m

Now, perimeter = 2 ( l+b)

Apply this formula:-

40 = 2 ( 2x + 10)

20 = 2x + 10

x = 5

So breadth is 5m and length is (5 + 10) = 15 m.

Answer 2

Answer :-

given perimeter = 40m

let the breadth be x , then length will be (x + 10)

we know that perimeter of rect = 2(L + B)

now, ATQ

2(x + 10 + x ) = 40

2(2x + 10) = 40

2x + 10 = 40/2

2x = 20 - 10

x = 10/2

x = 5

we conclude that the breadth of rect is 5 m and length of the rect = x + 10 i.e. (5 + 10)m = 15m..

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