Question

If the lenght of E. coli DNA is 1.36 mm, can you claculate the number of base pair in E. coli

Answer 1

Hi Montu !

Length of an E.coli DNA = No. of base pair × Distance between two base pair

We know that distance between two consecutive base pair is 0.34 × 10^-9 meter

So,
1.36 × 10-³ = bp × 0.34 × 10^-9
> bp = 4 × 10^6

Answer 2

Distance between two consecutive base pair = 0.34 nm

Total length of given DNA = 1.36mm  

∴ total no. of base pair =  1.36mm /0.34nm

⇒ 4 × 10⁶ Base pair.