Question

if the lenght of one of the equal sides pf an issosceles triangel is 4cm and base is 2cm then the area of triangel will be ​

Answer 1

Answer:

s=24+4+2=5

Area of the triangle

Δ=s(s−a)(s−b)(s−c)=5(5−4)(5−4)(5−2)=15cm2

Answer 2

Answer:

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