Question

if the lenght of the diagonla of a square is 16√2 then find the perimeter

Answer 1

Answer:

Let the diagonal be D cm and side be S cm . Then,

D= 16root2

In the right angle triangle,

S^2 +S^2 =D^2

256 *2 = 2* S^2

256= S^2

S = 16

Step-by-step explanation:

Answer 2

Answer:

64

Step-by-step explanation:

16^2×2=2×a^2

16^2=a^2

a=16

PERIMETER =4a

perimeter = 4×16

perimeter = 64