Question

If the length and breadth is 5 and 4 respectful. Then the perimeter, area and diagonal is​

Answer 1

$\tt \red{Answer:-}$

Perimeter of rectangle:- 2(length+breadth)

= 2(5+4)

= 2×9

= 18unit

Area of rectangle:- Length×breadth

= 5×4

= 20sq.unit

Diagonal of rectangle:- √5²+4²

$\tt{\sqrt{ {5}^{2} + {4}^{2} } }$

$= \rm{ \sqrt{25 + 16}}$

$= \rm{ \sqrt{41} }$

$= \tt{6.40}unit$

Hence, The perimeter of the rectangle is 18unit, the area of the rectangle is 20sq.cm and the diagonal of the rectangle is 6.40 unit.

Answer 2

Answer:

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Step-by-step explanation:

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