if the length and breadth of a cupid shaped object are in the rates of 5:3 and the volume is 180 cm³ and height of the object = 3cm
Answers
Let the length, breadth and height of the cuboid be 5x,3x and 2x respectively.
We know that the volume of the cuboid is l×b×h.
It is given that the volume of the cuboid is 35.937 m3, therefore,
35.937=5x×3x×2x⇒30x3=35.937⇒x3=3035.937=1.197⇒x=31.197⇒x=0.33
Therefore, the length l=5x=5×0.33=1.65, breadth b=3x=3×0.33=0.99 and height h=2x=2×0.33=0.66
Now, the total surface area of cuboid is 2(lb+bh+hl), therefore, the total surface area with length 1.65 m, breadth 0.99 m and height
Correct Question :
If the length and breadth of a Cuboid shaped object are in the ratio of 5:3 and the volume is 180 cm³ and height of the object is 3cm, find length and breadth of the object.
Given :
⬤ Length and Breadth of Cuboid are in the Ratio 5:3 .
⬤ Volume of Cuboid is 180 cm³ .
⬤ Height of Cuboid Shaped Object is 3 cm .
To Find :
⬤ Length and Breadth of Cuboid Shaped Object .
Formula Used :
Solution :
Let :
- Length of Rectangle be 5x
- Breadth of Rectangle be 3x
Now :
According to the Formula :
180 = l × b × h
180 = 5x × 3x × 3
180/3 = 15x²
60 = 15x²
60/15 = x²
√4 = x
2 = x
Therefore , The Value of x is 2
Hence ,
Length of Cuboid = 5x
= 5(2)
= 10
Breadth of Cuboid = 3x
= 3(2)
= 6
Therefore , Length of Cuboid is 10 cm and Breadth of Cuboid is 6 cm.
Check :
180 = L × b × h
180 = 10 × 6 × 3
180 = 60 × 3
180 = 180