if the length and breadth of a rectangle are double how many time the perimeter of the rectangle will that of the new rectangle
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let the length of rectangle be l and breadth be b
then the perimeter of rectangle =2(l+b)
if the length and breadth of a rectangle are double length becomes 2l and breadth becomes 2b
now perimeter =2(2l+2b)
4(l+b)
if the length and breadth of a rectangle are double the perimeter doubles
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