Question

if the length and breadth of a rectangle are doubled,how many times the p perimeter of the the old rectangle will that of the new rectangle new​

Answer 1

Answer:

let the length and the breadth be x and you

new length=2x

new breadth=27

old perimeter=2(x+y)

new perimeter

=2(2x+2y)

2X2(x+y)

by there ratio we find that the new perimeter is double that off the old perimeter

Answer 2

Answer:

2 times

Step-by-step explanation:

$perimeter= 4(l+b)$

New length 2l and 2b

$New perimeter = 4(2l+2b)$

Here we can see new perimeter = $8(l+b)$

It is doubled here