Math, asked by reedhima, 1 year ago

if the length and breadth of a rectangle are doubled how many times the perimeter of the old rectangle will that of the new rectangle be

Answers

Answered by abhi569
3
Let Lenght be x, and breadth be y

When lenght and breadth were as their original size,

Perimeter of rectangle =2(length + breadth)

Perimeter of rectangle =2(x+y)
___________________
When lenght and gets doubled,
Length =2x
Breadth =2y

Now, perimeter of rectangle =2(2x+2y)

Perimeter of rectangle =4(x+y)

Now,

[4(x+y)] /2(l+b)

=2

Now,

Perimeter of New rectangle is 2 times of the perimeter of old rectangle

I hope this will help you

-by ABHAY

reedhima: not understand last step
abhi569: Now
Answered by Cutiepie93
5
Hello friends!!

Here is ur answer :

Let the length be l.

Let the breadth be b.

Perimeter of old rectangle = 2 ( length +
breadth)

= 2 ( l + b )

According to question,

Length l of Rectangle be doubled.

It means l = 2l

Breadth b of Rectangle is also doubled.

It means b = 2b

Perimeter of new rectangle

= 2 ( 2l + 2b)

= 2 [ 2 ( l + b) ].

2 ( l + b) is Perimeter of old rectangle.

It means Perimeter of new rectangle is twice of Perimeter of old rectangle.


HOPE IT HELPS YOU..
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