Question

If the length and breadth of a rectangle are triple how many times the perimeter of the old rectangle will that of the new rectangle be

Answer 1

Step-by-step explanation:

Let the length of old rectangle = l

Let the length of old rectangle = lLet the breadth of old rectangle = b

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, then

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, thenlength of the new rectangle = 2l

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, thenlength of the new rectangle = 2lbreadth of the new rectangle = 2b

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, thenlength of the new rectangle = 2lbreadth of the new rectangle = 2b∴ Perimeter of new rectangle = 2(length + breadth)

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, thenlength of the new rectangle = 2lbreadth of the new rectangle = 2b∴ Perimeter of new rectangle = 2(length + breadth)= 2(2l + 2b)

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, thenlength of the new rectangle = 2lbreadth of the new rectangle = 2b∴ Perimeter of new rectangle = 2(length + breadth)= 2(2l + 2b)= 2 × 2(l + b)

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, thenlength of the new rectangle = 2lbreadth of the new rectangle = 2b∴ Perimeter of new rectangle = 2(length + breadth)= 2(2l + 2b)= 2 × 2(l + b)= 2 × perimeter of the old rectangle [∵ perimeter of old rectangle = 2(l + b)]

Let the length of old rectangle = lLet the breadth of old rectangle = bPerimeter of the old rectangle = 2(length + breadth) = 2(l + b)When the length and the breadth of the rectangle are doubled, thenlength of the new rectangle = 2lbreadth of the new rectangle = 2b∴ Perimeter of new rectangle = 2(length + breadth)= 2(2l + 2b)= 2 × 2(l + b)= 2 × perimeter of the old rectangle [∵ perimeter of old rectangle = 2(l + b)]Hence, the perimeter of the new rectangle will become two times of the perimeter of the old rectangle.

Answer 2

Step-by-step explanation:

Hence, the perimeter of the new rectangle will become two times the perimeter of the old rectangle.

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