Question

If the length and breadth of a rectangle both made half, then perimeter of rectangle is how many times of the given rectangle?

Answer 1

Let the length be l and breadth be b.
So perimeter of original triangle is 2(l+b)
Now if both l an b gets half
Length of new triangle =L/2 and breadth =b/2
New perimeter = 2(1/2*L+1/2* b)
=2*1/2(L+b)
=(L+b)

Answer 2

Hi Yukta,

Let initially length and breadth of the rectangle be l , b
given perimeter = 2l + 2b = 2(l+b)

now when both l and b are made half, l/2 and b/2
new perimeter =  2(l/2 + b/2) = 2 * 1/2 (l+b)

so
new perimeter / given perimeter
= 2(l+b) / (l+b)
= 2

so the new perimeter will be 2 times the given perimeter

Hope it helps.
Let me know if any doubts.
Cheers !!!