if the length and breadth of a rectangle both made half , then perimeter of rectangle is how many times of the given rectangle?
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The perimeter of the new rectangle is half of that of the given rectangle.
Step-by-step explanation:
Let's assume that, the length of the original rectangle is 2l
And the breadth of the same rectangle is 2b
Therefore, the perimeter of that rectangle is 2(2l + 2b) = 4(l + b)
Now the length and breadth is halved,
Therefore, the new length is l and the new breadth is b
And the new perimeter is 2(l + b)
Therefore, the original perimeter, 4(l + b) = 2 times 2(l + b) = 2 times the new perimeter.
Therefore, the perimeter of the new rectangle is half of that of the given rectangle.
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