Question

if the length and breadth of a rectangle by what percentage increase​

Answer 1

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A = L * W

(W will be “breadth”).

1.15L + 1.2W = XA

where x is the percentage increase.

Multiply the coefficient of L and W to find X:

1.15 * 1.2 = 1.38

So a 15% increase in length and a 20% increase in breadth will result in a 38% increase in area.

You can prove this by substituting actual numbers for L and W. For the sake of argument we’ll set L equal to 10, and W equal to 20:

A = L * W

L = 10

W = 20

A = 10 * 20

A = 200

1.15L * 1.2W = XA

L = 10

W = 20

(1.15*10) * (1.2*20) = 200X

11.5 * 24 = 200X

276 = 200X

Divide by 200:

276/200 = X

Reduce, with a GCF of 4:

69/50 = x

You can put this into a calculator to calculate it and convert to decimal quicker. The result is 1.38, or a 38% increase.

Answer 2

$\huge\color{yellow}\boxed{\colorbox{black}{Añswēr❗}}$

A = L * W

(W will be “breadth”).

1.15L + 1.2W = XA

where x is the percentage increase.

Multiply the coefficient of L and W to find X:

1.15 * 1.2 = 1.38

So a 15% increase in length and a 20% increase in breadth will result in a 38% increase in area.

You can prove this by substituting actual numbers for L and W. For the sake of argument we’ll set L equal to 10, and W equal to 20:

A = L * W

L = 10

W = 20

A = 10 * 20

A = 200

1.15L * 1.2W = XA

L = 10

W = 20

(1.15*10) * (1.2*20) = 200X

11.5 * 24 = 200X

276 = 200X

Divide by 200:

276/200 = X

Reduce, with a GCF of 4:

69/50 = x

You can put this into a calculator to calculate it and convert to decimal quicker. The result is 1.38, or a 38% increase.