If the length and breadth of a rectangle is double d how many time s will the perimeter of the new rectangle be that of the original rectangle?
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when length is l and breadth is b
perimeter of rectangle = 2(l+b)
now the condition is l = 2l and b = 2b
therefore perimeter = 2(2l+2b)
= 2(2(l+b))
it means when length and breadth are doubled of a rectangle then perimeter will also become doubled
perimeter of rectangle = 2(l+b)
now the condition is l = 2l and b = 2b
therefore perimeter = 2(2l+2b)
= 2(2(l+b))
it means when length and breadth are doubled of a rectangle then perimeter will also become doubled
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Hey✌✌
let the length and width of rectangle be a and b
Perimeter = 2(a+b)
New length = 2a
New breadth = 2b
New perimeter = 2(2a+2b)
=. 4( a + b)
Hence , perimeter of new rectangle is 2 times that of original one .
let the length and width of rectangle be a and b
Perimeter = 2(a+b)
New length = 2a
New breadth = 2b
New perimeter = 2(2a+2b)
=. 4( a + b)
Hence , perimeter of new rectangle is 2 times that of original one .
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