Question

if the length and breadth of a rectangular painting are 4xy3 and 3x2y find its area? step by step
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Answer 1

Answer:

Required area is 12x³y⁴ square unit.

Step-by-step explanation:

Given,the length and breadth of a rectangular painting are 4xy3 and 3x2y.

So, length $= 4x {y}^{3}$

and breadth $= 3 {x}^{2} y$

Here we want to find area of the rectangular painting.

We know,area of the rectangle = length × breadth

So,area

$= 4x {y}^{3} \times 3 {x}^{2} y \\ = 12 {x}^{1 + 2} {y}^{3 + 1} \\ = 12 {x}^{3} {y}^{4}$

Therefore, required area is 12x³y⁴ square unit.

Rectangle related more information:

A quadrilateral with four right angles is called rightangle. It can also be defined as: an equiangular quadrilateral, since equiangular means that all its angles are equal; or a parallelogram containing a right angle. A rectangle has four sides of equal length is a square.

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Answer 2

Answer:

the area of the rectangular painting is $36x^2*y^3$.

Step-by-step explanation:

The area of any shape is the number of unit squares that can fit into it. Here "unit" refers to one (1) and a unit square is a square with a side of 1 unit. So, the area of a rectangle is the number of unit squares within the boundary of the rectangle. Alternatively, the space occupied within the perimeter of this shape is called the area of the rectangle.

The area of a rectangle is found by multiplying its length and breadth.

Given that the length of the rectangular painting is$4xy3$and breadth is 3x2y, the area of the painting can be found by:

Area = Length * Breadth

$= 4xy3 * 3x2y$

$= 12x^2y^23y$

$= 36x^2*y^3$

So, the area of the rectangular painting is $36x^2*y^3.$

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