Math, asked by ankita5550, 1 year ago

if the length and breadth of a rectangular room are each increased by 1 m, then the area of floor is increased by 21 sq. m. if the length is creased by 1 m and breadth is decreased by 1m, then the area is decreased by 5 sq. m. the perimeter of the floor is: ?

Answers

Answered by Anonymous
6
aaliayasin272Helping Hand
Let the length and breadth of a room be x & y
Area of the room = x * y
When the length and breadth of a room are increased by 1 metre, then the new dimensions of the room would be
Length : x+1
Width : y+1
New area = (x+1)(y+1)
Since the area is increased by 21 metres, therefore
(x+1)(y+1)- xy = 21...........(1)
Further when the length is increased by 1 metre, then the area would be (x+1) * y
Now when the length is increased by 1 metre , the area is dcreased by 5 square metres
(x+1) * y -xy = 21-5............(2)
Simplifying & solving eqns 1 & 2 results in
x=4 and y=16
Perimeter of the room = 2*(Length+width)
= 2*(4+16)
Ans : 40 meter

Anonymous: thanks ✌
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