Math, asked by harshakrishnaswamy, 2 months ago

If the length and breadth of a rectangular wall are 93 cm cm and 60 cm respectively, at least how many identical square tiles of side length 15 cm are needed to entirely cover the area of the wall?

Answers

Answered by Mister36O
8

Step-by-step Explanation :

Given that :

ㅤㅤ Length of a rectangular wall = 93 cm.

ㅤㅤ⇒ Breadth of the rectangular wall = 60 cm.

ㅤㅤ⇒ Length of side of square tiles = 15 cm.

To find :

ㅤㅤNo. of square tiles needed to entirely cover the area of the wall.

Finding the no. of square tiles :

Area of rectangular wall :

ㅤㅤ→ Area of rectangle = l × b.

ㅤㅤ→ Area of rectangle = 93 cm × 60 cm.

ㅤ .°. Area of rectangle = 5580 cm².

Area of 1 square tile :

ㅤㅤ→ Area of square = (side)².

ㅤㅤ→ Area of square = (15²) cm².

ㅤㅤ→ Area of square = (15 × 15) cm².

ㅤ .°. Area of square = 225 cm².

No. of tiles required :

ㅤㅤ→ No. of tiles required = (Area of wall)/(Area of 1 square tile).

ㅤㅤ→ (5580)/(225).

ㅤㅤ→ (1116)/(45).

ㅤㅤ→ (124)/(5) 24.8.

.°. No. of tiles required = 24.8 tiles.

Answered by Dhratinahar
9

Answer:

24.8

Step-by-step explanation:

We are given length & breadth of a rectangle.

We have to first fine the area of the rectangle

  • Area = l * b
  • 93*60
  • 5,580

Now, we have to find the area of the tile

  • Area = s*s
  • 15 * 15
  • 225

Finally, to get the answer we will have to divide the area of the rectangle by the area of the tile

  • 5580 / 225
  • 24.8 tiles.

Now we cannot buy a half tile that's why the estimated answer will 25.

Hope this answer helps you

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