Question

if the length and breadth of rectangle is subtracted by 5 then the perimeter of rectangle is 26 what is a mathematical statement for the condition

Answer 1

let the length be X and the breadth be y.
so,
2(x-5+y-5)=26
2(X+y-10)=26
X+y-10=13
X+y=23




hope this helps you..please mark me as brainliest

Answer 2

Let the length and breadth of the rectangle be x and y respectively.
Therefore,
Perimeter of rectangle=2(x+y)
When length and breadth are subtracted by 5,then:
Breadth=y-5
Length =x-5
Perimeter =2(x-5+y-5)
ATQ,
26=2(x-5+y-5)
26=2(x+y-10)
x+y-10=26/2
X+y=13+10
x+y=23
x+y-23=0
Hope it helps you.
Plz Mark it as brainliest.