Question

if the length and breadth of the rectangle is 5y + 4,2y + 36 and perimeter is 220 cm find y

Answer 1

Perimeter = 2 (l+b)
220 = 2{(5y+4) + (2y+36)}
220/2 = 7y + 40
110 = 7y + 40
110-40 = 7y
70 = 7y
70/7 = y
10 = y

Hence, the value of y is 10....

Hope it will help you...

Answer 2

$Given \:$

$Length \: of \: the \: rectangle \: = \: 5y + 4$

$Breadth \: of \: the \: rectangle \: = \: 2y + 36$

$Perimeter \: of \: the \: rectangle \: = \: 220cm$

$Perimeter \: of \: the \: rectangle \: = \: 2(l + b)$

$220 = 2(5y + 4 + 2y + 36)$

$220 = 10y + 8 + 4y + 72$

$220 = 14y + 80$

$220 - 80 = 14y$

$140 = 14y$

$140 \div 14 = y$

$10 = y$

$Therefore \: the \: value \: of \: y \: = \: 10$

$Substitute \: 10 \: in \: place \: of \: y$

$Length \: = \: 5(10) + 4 = 50 + 4 = 54cm$

$Breadth = \: 2(10) + 36 = 20 + 36 = 56cms$

$Therefore=> \:$

$The \: length \: of \: the \: rectangle \: = \: 54cms$

$The \: breadth \: of \: the \: rectangle \: = \: 56cms$