Question

if the length and breadth of the rectangle R double how many time the perimeter of the old rectangle will that of the new rectangle be?​

Answer 1

Answer :

Let the old rectangle's length be L and breath be B

Perimeter,.$P1 = 2(L+B)$ ______(1)

When Length and breath is doubled length and breath will be 2L and 2B respectively

Perimeter, $P2 = 2(2L+2B)$

$P2 = 4(L+B)$. ______(2)

dividing equation (2) by (1)

we get,

$P2/P1 = 4(L+B)/2(L+B)$

= $P2=2*P1$

The new rectangle will be 2 times the old rectangle

hope it helps you