Question

IF THE LENGTH AND BREATH OF A GARDEN ARE 45 1/2 M AND 23 1/2 M,FIND THE LENGTH OF THE BARBED WIRE REQUIRED TO BUILD A TWO LAYER FENCE AROUND IT.

Answer 1

Solution

Given :-

• Length of Garden = 45(1/2) m
• Breadth of Garden = 23(1/2) m

Find :-

• Length of wire to build a two layer fence around it .

Explanation

Using Formula

★ Perimeter of rectangular Garden = 2 × (Length + Breadth)

Here,

• Length of rectangular garden = 45(1/2) =91/2 m
• Breadth of rectangular Garden = 23(1/2) =47/2 m

So, Now calculate perimeter

==> Perimeter of rectangular Garden = 2 × (91/2 + 47/2)

==> Perimeter of rectangular Garden = 2 × ( 91 + 47)/2

==> Perimeter of rectangular Garden = 2 × 138/2

==> Perimeter of rectangular Garden = 138 m

Here,

For one round of wire around the whole Rectangular garden required be = 138 m

So,

Its will be required for two round = 138 × 2 = 276 m

____________________

Answer 2

Answer:

276 m of wire is required to build a two-layer fence around the garden.

Step-by-step explanation:

Given:

$\sf{Length \; of \; the \; garden = 45 \; \dfrac{1}{2} \; m = \dfrac{91}{2} \; m}$

$\sf{Breadth \; of \; the \; garden = 23 \; \dfrac{1}{2} \; m = \dfrac{47}{2} \; m}$

To find:

Length of the wire required to build two-layer fence around the garden.

Solution:

As we know,

Perimeter of rectangle (garden)  = 2(length + breadth)

Substituting the values,

$\sf{Perimeter \; of \; the \; garden = 2 \times \left( \dfrac{91}{2} + \dfrac{47}{2} \right)}$

$\hookrightarrow \sf{2 \times \left( \dfrac{91+47}{2} \right)}$

$\hookrightarrow \sf{2 \times \dfrac{138}{2} }$

$\hookrightarrow \sf{138 \; m}$

Now,

$\sf{Length \; of \; the \; wire \; required =2 \times perimeter}$

Substituting the values,

$\sf{Length \; of \; the \; wire \; required =(2 \times 138) \; m}$

$\hookrightarrow \sf{276 \; m}$

Hence,

The length of required wire = 276 m