Question

If the length and breath of a rectangle are (10-x)&(x+3) find the area of rectangle

Answer 1

hey
here's your answer!

#length = (10-x)
#breadth = (x+3)
AREA OF A RECTANGLE = length * breadth
= (10-x)(x+3)
= 10(x +3) -x(x+3)
= 10x +30 - x² - 3x
= 30 + 7x -x² [answer]

Hope it helps!

Answer 2

If Length = 10-x ( Multiplying both sides by (-), we obtain -(10-x)= -10+x)
               = x-10
Breadth = x+3
Then, area = l X b
             = (x-10) X (x+3)
             = (x)² + x (-10+3) +(-10X3)  {Using identity, (x+a)(x+b)=x²+x(a+b)+ab
             = x²-10x+3x-30
             = x²-7x-30.
Hence, the area of rectangle is x²-7x-30.

                                     ↔↔↔↔↔↔↔↔↔↔↔↔↔

Hope it helps you
Please mark as brainliest