If the length and breath of a rectangle are (10-x)&(x+3) find the area of rectangle
Answers
Answered by
1
It is simple mate....
Area of a rectangle
= Length × Breadth
![= (10 - x)( x + 3) \\ = 10x + 30 - {x}^{2} - 3x \\ = - {x}^{2} + 7x + 30 = (10 - x)( x + 3) \\ = 10x + 30 - {x}^{2} - 3x \\ = - {x}^{2} + 7x + 30](https://tex.z-dn.net/?f=+%3D+%2810+-+x%29%28+x++%2B+3%29+%5C%5C++%3D+10x+%2B+30+-++%7Bx%7D%5E%7B2%7D++-+3x+%5C%5C++%3D++-++%7Bx%7D%5E%7B2%7D++%2B+7x+%2B+30)
So
![- {x}^{2} + 7x + 30 - {x}^{2} + 7x + 30](https://tex.z-dn.net/?f=+-++%7Bx%7D%5E%7B2%7D++%2B+7x+%2B+30)
is the right answer.
If it helped you PLEASE MARK MY ANSWER AS THE BRAINLIEST ANSWER
Area of a rectangle
= Length × Breadth
So
is the right answer.
If it helped you PLEASE MARK MY ANSWER AS THE BRAINLIEST ANSWER
Similar questions