Physics, asked by Tharinish, 8 months ago

If the length and time period of an oscillating pendulum have errors of 1 percent and 3 percent respectively then the error in measurement of acceleration due to gravity is

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Answered by VIVEKPARIDA
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Now, |ΔL/L| = 0.01 and |ΔT/T|=0.03. So, |Δg/g| = 0.07. Hence, the relative error in the measurement of gravity is 7%

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