Question

If the length and time period of an oscillating pendulum have errors of 1% and 3% respectively then the error in measurement of acceleration due to gravity is​

Answer 1

Answer:

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Answer 2

Answer:

7 %

Explanation:

We know,

Time period , T = 2π√(l/g)

Taking square both sides,

T² = 4π²l/g ⇒g = 4π²l/T²

So, for finding error in accelerating due to gravity we have to take formula,

% error in g = % error in l + 2 × % error in T

Given,

% error in l = 1 %

% error in T = 3 %

∴ % error in g = 1 % + 2 × 3 % = 7 %