If the length and time period of an oscillating pendulum have errors of 1% and 3% respectively then the error in measurement of acceleration due to gravity is
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It would be 7°/₀....................................
We know that g = T²/ 4π²l
Δg/g = 2ΔT/T + Δl/l = 3 *2 + 1 = 7
Hassan05:
can you send me the steps?
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Hope it's help you.✌️✌️
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it's by mistake
in acceleration due ro gravity
due to
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