Question

if the length and width of a rectangle are doubled. how percent of area increased
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Answer 1

Answer:

4 times

Step-by-step explanation:

let length(l) be xcm

breadth(b) be y cm

area(a) of rectangle =(l×b)unit²

xy cm²

if doubled l=2x cm

b =2y cm

a = 2x×2y cm²

4xy cm²

compare and then u see it's 4 times increased

Answer 2

Answer:

$300$%

Step-by-step explanation:

Let us assume the length be $2$ and width $1$ of the rectangle.

Area of rectangle $=$ Length × Width$=2$×$1=2$

Now, According to the question, if the length and width are doubled

New length $=4$ and New width $=2$.

So,

The new area of the rectangle will be $=$ Length × Width$=4$×$2=8$.

Here we can see that the area of the rectangle increased by $6$, which is $300%$% of $2$.