If the length breadth and height of a room are 22•5m ×10m×7•5m find the area of painting of that room.
Answers
Answered by
1
Step-by-step explanation:
It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.
Area of four walls of the room is: 2h(l+b)
A=2h(l+b)=2×3(8+5)=6×13=78 m
2
Area of the ceiling is:
A=l×b=8×5=40 m
2
Total area of the four walls and the ceiling of the room is 78+40=118 m
2
It is given that cost of white washing is Rs.15/m
2
, therefore,
Total cost of white washing is:
118×15=1770
Hence, the cost of white washing the walls is Rs.1770.
Answered by
0
Answer:
lateral surface area of cuboid =2（l+b）h
=2（22.5+10）7.5
=487.5
The area of paintimg of that room is 487.5 sq.m
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