If the length of a certain rectangle is decreased by 4 cm and width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle. pls explain the sum
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Answer:
50m
Step-by-step explanation:
Let length = l
length =ω⇒
(1) l − 4 = ω+3 ... (1)
⇒l = ω + 7
(2) l.ω = (l−4) (ω+3)
(ω+7) (ω) = (ω+3)^2
ω^2 + 7ω = ω^2 + 9 + 6ω
ω=9⇒l = 16
∴ Perimeter = 2(l+ω)
=2 (9+16) = 2×25
=50m
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