If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm square with the same area as the original rectangle would result . Find the perimeter of the original rectangle.
Please give the answer.
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Let length =l length =ω⇒
(1)l−4=ω+3...(1)
⇒l=ω+7
(2)l.ω=(l−4)(ω+3)
(ω+7)(ω)=(ω+3)
2
ω
2
+7ω=ω
2
+9+6ω
ω=9⇒l=16
∴ Perimeter =2(l+ω)
=2(9+16)=2×25
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