Question

If the length of a certain rectangle is decreased by 4cm and the width is increased by 3cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.​

Answer 1

Step-by-step explanation:

Let,

The length of the rectange be ‘X’

and the width be ‘Y’

Area =XY

According to question,

Decreased length =X-4

increased width=Y+3

Area of the square formed= (X-4)(Y+3)

ATQ,

XY=(X-4)(Y+3)………..(1)

and,x-4=y+3 ……………(2)…{as it is square}

On solving 1 and 2 you will get,

X=16 and Y=9

Perimeter of the original reactangle =2(x+y)

Or,2(16+9)=50

HOPE IT HELPS YOU