Question

If the length of a chord of a circle is 16 cm and the distance of the chord from the center is 6 cm, find the radius of the circle

Answer 1

If O is the center of the circle.. And AB is the chord.. And the distance of the chord from the center is OD... So.. AB _|_ OD
Now triangle ODB is a right angle triangle..
So OB^2=OD^2+DB^2
OB^2= 6×6+8×8 [OD=6, DB=AB/2=16/2=8]
=100
OB=10
the radius of the circle is 10cm

Answer 2

If O is the center of the circle.. And AB is the chord.. And the distance of the chord from the center is OD... So.. AB _|_ OD

Now triangle ODB is a right angle triangle..

So OB^2=OD^2+DB^2

OB^2= 6×6+8×8 [OD=6, DB=AB/2=16/2=8]

=100

OB=10

the radius of the circle is 10cm