Question

If the length of a chord of a circle is 48cm and the distance of it from the centre is 7cm . then let us write by calculating, the length of the chord which is 20cm . distance away from the center of the circle. ​

Answer 1

Answer:

Solution

Let AB and PQ are two chords of the circle with centre at O , OC and OD are two perpendicular draw form O to AB and PQ respectively.As per question , OC = 7 cm

AB = 48 cm , OD = 20 cm , PQ = ?

Now AB = 48 cm ,

∴BC= 1/2×48cm =24cm

Then , form the right angled triangle OBC we get ,

OB^2= BC^2 +OC^2 or OB^2= 24

OB^2= 576+49 or OB^2= 625 or

∴OQ=25 cm

∵OB=OQ

OQ,OQ^2 = OD^2 + DQ^2

or

(25)^2 = (20)^2 + DQ^2 or 625= 4

∴PQ=2DQ= 3× 15 cm

PQ = 30 cm

Explanation:

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