If the length of a chord of circle is 32cm and distance of a chord from the center of the circle is 12cm then the diameter of a circle?
Answers
Answered by
13
Hey Mate your answer is
By Pythagoras Thearom
In ∆AOB angle A is 90°
(Reason: Perpendicular drawn from the centre of the circle to the chord bisects the chord)
length of the chord= 32/2=16
(OA)²+(AB)²=(OB)²
(12)²+(16)²=(OB)²
144+256=(OB)²
400=(OB)²
OB =20cm
Now,
Diameter = radius ×2
=20×2
=40cm
Therefore the diameter is 40 cm
Hope it will help you
Mark me Brainiest
Thanks for Question
Follow me!!!!!
By Pythagoras Thearom
In ∆AOB angle A is 90°
(Reason: Perpendicular drawn from the centre of the circle to the chord bisects the chord)
length of the chord= 32/2=16
(OA)²+(AB)²=(OB)²
(12)²+(16)²=(OB)²
144+256=(OB)²
400=(OB)²
OB =20cm
Now,
Diameter = radius ×2
=20×2
=40cm
Therefore the diameter is 40 cm
Hope it will help you
Mark me Brainiest
Thanks for Question
Follow me!!!!!
Similar questions