Question

if the length of a conductor is increased by 10% on stretching what will be the effect on its new resistance​

Answer 1

Answer:

If volume and density remains same, then resistance of wire:

R∝l2

where l is length of the wire

∴R′=(1+10010l)2=(1011)2R

Hence, RR′−R=10021=21%

Therefore, change in resistance of wire = 21%

Explanation:

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