Question

If the length of a cylinder is 1 =
(4.00+0.001) cm, radius r = (0.0250
+0.001) cm and mass m = (6.25+0.01)
gm. Calculate the percentage error in the
determination of density.
[Ans: 8.185%]​

Answer 1

Answer:

The answer is 8.185%

Explanation:

If the length of a cylinder is L=(4.00±0.001) cm, the radius of cylinder is R=(0.0250 ±0.001) cm and mass of the cylinder is M=(6.25±0.01) gm.

We know the density formula of the cylinder is (π x length x radius^2)

So the corresponding value of error of density (as values given in the question) is,

[(0.001/4)x100]+[(2x(0.001/0.025))x100]+[(0.01/6.25)x100]

=> (0.1/4)+(0.2/0.025)+(1/6.25)

=> 0.025+8+0.16

=> 8.185