If the length of a cylinder is l = (4.00 ± 0.01) cm, radius r = (0.250 ± 0.01) cm and mass m = 6.25 ± 0.01 g. Calculate the percentage error in determination of density.
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Answer:
the percentage error in determination of density = 8.41 %
Explanation:
length of a cylinder is l = (4.00 ± 0.01) cm,
radius r = (0.250 ± 0.01) cm
Volume of Cylinder = πr²l
mass m = 6.25 ± 0.01 g
Density = Mass/Volume
=> Density = m/πr²l
Fractional Error
ΔD/D = Δm/m + 2Δr/r + Δl/l
=> ΔD/D = 0.01/6.25 + 2*0.01/0.25 + 0.01/4
=> ΔD/D = 0.0016 + 0.08 + 0.0025
=> ΔD/D = 0.0841
the percentage error in determination of density. = 100 * 0.0841
= 8.41 %
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