Question

if the length of a diagonal of a quadrilateral is 10 cm and length of the perpendiculars on it from opposite vertices are 4 cm and 6 CM then area of quadrilateral is

Answer 1

area of quadrilateral = 1/2(sum of perpendiculars dropped from opposite sides)diagonal
=1/2×(4+6)×10
5×10 cm square
=50 cm square

Answer 2

Answer:

Area of the quadrilateral = 50 $cm^{2}$

Step-by-step explanation:

the length of a diagonal of quadrilateral  = 10 cm

length of the perpendicular on it opposite vertices are 4 cm, 6 cm

area of the quadrilateral =  $\frac{1}{2} ( dagonal)$ $(perpendicular heights )$

                                          = $\frac{1}{2}$ (10)( 4+6)

                                          =  5(10) = 50  $cm^{2}$

the area of the quadrilateral = 50 $cm^{2}$