Question

If the length of a filament of a heater is reduced by 10% the power of the heater will be

Answer 1

Answer:

the lenght of filament of a heater is reduced 100%the power of the heater will be.

Answer 2

Answer:

we know that P=V^2/R

=V^2/ρl/A

P'=1/(l-10/100l)

P'/P=l/(l-l/10)=10/9

P'-P/P*100=10/9*100

=11%

SO it increases by 11%

Hence, the power of the heater will increase by about 11%.