Math, asked by 12062016, 1 year ago

.
If the length of a rectangle increased by the ratio
of 10:11and its breadth increases by the ratio
8:15, then its area increase by the ratio of​?

Answers

Answered by anita833
1

Answer:

Step-by-step explanation:

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Answered by sharonr
0

If the length of a rectangle increased by the ratio  of 10:11 and its breadth increases by the ratio  8:15, then its area increase by the ratio of​ 16 : 33

Solution:

According to question, length of a rectangle is increased by the ratio 10:11

So, let the original length be 10x and new length be 11x  

Also, breadth increases by ratio 8:15 so, let the original breadth be 8y and new breath be 15y

\begin{array}{l}{\text { Area of old Rectangle }=\text { old length } \times \text { old breadth }} \\\\ {\text { Area of old Rectangle }=10x \times 8y=80xy}} \\\\ {\text { Area of New Rectangle }=\text { new length } \times \text { new breadth }} \\\\ {\text { Area of New Rectangle }=11x \times 15 y}=165xy}}\end{array}

\text { Ratio }=\frac{\text { Area of old Rectangle }}{\text { Area of new Rectangle }}=\frac{80 x y}{165 x y}=\frac{80}{165}=\frac{16}{33}

Hence the area increase by the ratio of 16:33

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