Question

If the length of a rectangle is 10 more than its breadth and perimeter is 60 Find its length and breadth

Answer 1

Answer:

let breadth be xcm

then length is (x+6)cm

now perimeter=2(l+b)

but perimeter is 60(given)

this 2(l+b)=60

now 2(x+6+x)=60cm

now 2(2x+6)=60çm

now 4x+12=60cm

4x=60-12=48cm

4x=48cm x=(48/4)cm=12cm

now breadth=12cm

and lenght=x+6=12+6=18cm

now area= l×b= 12×18=216cm2

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given a rectangle whose length is 10 m more than its breadth
• Perimeter of rectangle is 60 m

To Find:

• We have to find the dimensions of rectangle

Figure of Rectangle:

$</p><p>\textsf{\qquad \qquad \: \,---------- Length----------\longrightarrow}\\</p><p>\sf{Breadth} \begin{cases}</p><p>\boxed{\begin{minipage}{4cm}</p><p>\textsf{ \\ \\ \\ \\ \\ }</p><p>\end{minipage}}</p><p>\end{cases}</p><p>$

Solution:

Let breadth of rectangle = x

Length of rectangle = ( x + 10 )

$\boxed{\sf{\pink{Perimeter = 2(Length + Breadth) }}}$

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$\bigstar \: \: \underline{\large\mathfrak\orange{According \: to \: the \: Question:}}$

$\hookrightarrow \boxed{\sf{Perimeter = 60 m}}$

$\hookrightarrow \sf{ \: 2(Length + Breadth) = 60}$

Substituting the values

$\hookrightarrow \sf{ \: 2( x + 10 + x ) = 60}$

$\hookrightarrow \sf{ \: 2( 2x + 10 ) = 60}$

$\hookrightarrow \sf{ \: 2x + 10 = \dfrac{60}{2}}$

Solving the Equation

$\hookrightarrow \sf{ \: 2x + 10 = 30}$

$\hookrightarrow \sf{ \: 2x = 30-10}$

$\hookrightarrow \sf{ \: 2x = 20}$

$\hookrightarrow \sf{ \: x = \dfrac{20}{2} }$

$\hookrightarrow \sf{ \: x = \cancel{\dfrac{20}{2}} }$

$\hookrightarrow \boxed{\sf{ \: x = 10 }}$

Hence value of x is 10 m

________________________________

Finding the dimensions:

$\implies \sf{Breadth = 10 m}$

$\implies \sf{Length = 10 + 10 }$

$\implies \sf{20 m}$

$\boxed{\large\mathfrak\red{Length \: of \: Rectangle = 20 m}}$

$\boxed{\large\mathfrak\red{Breadth \: of \: Rectangle = 10 m}}$

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$\huge\mathfrak\green{Verification:}$

1 ) Length is 10 more than Breadth:

$\implies \sf{Length - Breadth}$

$\implies \sf{20 - 10}$

$\implies \sf{10}$

2 ) Perimeter of rectangle is 60 m:

$\implies \sf{Perimeter = 2(Length + Breadth)}$

$\implies \sf{2(20+10)}$

$\implies \sf{2 \times 30}$

$\implies \sf{60 m}$

Hence Verified !